Mathematics

Mathematics

Problem

If a×(b×c)\mathbf{a} \times (\mathbf{b} \times \mathbf{c}) is perpendicular to (a×b)×c(\mathbf{a} \times \mathbf{b}) \times \mathbf{c} , we may have a. (a⋅c)∣b∣2=(a⋅b)(b⋅c)(\mathbf{a} \cdot \mathbf{c})|\mathbf{b}|^2 = (\mathbf{a} \cdot \mathbf{b})(\mathbf{b} \cdot \mathbf{c}) b. a⋅b=0\mathbf{a} \cdot \mathbf{b} = 0 c. a⋅c=0\mathbf{a} \cdot \mathbf{c} = 0 d. b⋅c=0\mathbf{b} \cdot \mathbf{c} = 0

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