Chemistry

Chemistry

Problem

The equilibrium : Cr2O72−+H2O⇌2CrO42−+2H+\text{Cr}_2\text{O}_7^{2-} + \text{H}_2\text{O} \rightleftharpoons 2\text{CrO}_4^{2-} + 2\text{H}^+ exist at pH=4\text{pH} = 4. The concentration of [CrO42−][\text{CrO}_4^{2-}] at equilibrium is : a. 4×Kc×[Cr2O72−]4 \times K_c \times [\text{Cr}_2\text{O}_7^{2-}] b. 2×Kc⋅[Cr2O72−]2 \times \sqrt{K_c} \cdot [\text{Cr}_2\text{O}_7^{2-}] c. 104×Kc×[Cr2O72−]10^4 \times \sqrt{K_c} \times [\text{Cr}_2\text{O}_7^{2-}] d. 10−8×Kc×[Cr2O72−]10^{-8} \times K_c \times [\text{Cr}_2\text{O}_7^{2-}]

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