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Problem
Problem
In an ambiguous case of solving a triangle when
a
=
5
a = \sqrt{5}
a
=
5
,
b
=
2
b = 2
b
=
2
,
∠
A
=
π
6
\angle A = \frac{\pi}{6}
∠
A
=
6
π
and the two possible values of third side are
c
1
c_1
c
1
and
c
2
c_2
c
2
, then a.
∣
c
1
−
c
2
∣
=
2
6
|c_1 - c_2| = 2\sqrt{6}
∣
c
1
−
c
2
∣
=
2
6
b.
∣
c
1
−
c
2
∣
=
4
6
|c_1 - c_2| = 4\sqrt{6}
∣
c
1
−
c
2
∣
=
4
6
c.
∣
c
1
−
c
2
∣
=
4
|c_1 - c_2| = 4
∣
c
1
−
c
2
∣
=
4
d.
∣
c
1
−
c
2
∣
=
6
|c_1 - c_2| = 6
∣
c
1
−
c
2
∣
=
6
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