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Mathematics
Mathematics
Problem
The area bounded by the curve
y
2
=
4
x
y^2 = 4x
y
2
=
4
x
and the circle
x
2
+
y
2
−
2
x
−
3
=
0
x^2 + y^2 - 2x - 3 = 0
x
2
+
y
2
−
2
x
−
3
=
0
is a.
2
π
+
8
3
2\pi + \frac{8}{3}
2
π
+
3
8
b.
4
π
+
8
3
4\pi + \frac{8}{3}
4
π
+
3
8
c.
π
+
8
3
\pi + \frac{8}{3}
π
+
3
8
d.
π
−
8
3
\pi - \frac{8}{3}
π
−
3
8
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