A Modern Approach to Quantum Mechanics · Problem 11.16

Identical Particles — John S. Townsend

Physics — Quantum Mechanics · hydrogen-expectation-1-over-r

Problem

In order to evaluate ⟨1/r⟩\langle 1/r \rangle consider γ/r\gamma/r as a perturbation for the hydrogenic atom, where we can think of γ\gamma as some "small" constant. The first-order shift in the energy is given by En(1)=⟨γr⟩n,l,mE_n^{(1)} = \left\langle \frac{\gamma}{r} \right\rangle_{n,l,m} which is clearly linear in γ\gamma. (a) First show that the exact eigenvalues are given by En=−μ(Ze2−γ)22ℏ2n2E_n = -\frac{\mu(Ze^2 - \gamma)^2}{2\hbar^2 n^2} *Suggestion:* Examine (10.32). (b) Since En=En(0)+En(1)+En(2)+⋯E_n = E_n^{(0)} + E_n^{(1)} + E_n^{(2)} + \cdots, we can obtain En(1)E_n^{(1)} either by explicitly finding the contribution to EnE_n that is linear in γ\gamma, or, more generally, noting that En(1)=γ(dEndγ)γ=0E_n^{(1)} = \gamma\left(\frac{dE_n}{d\gamma}\right)_{\gamma=0} since En(0)E_n^{(0)} is of course independent of γ\gamma and the higher order terms in the expansion are at least of order γ2\gamma^2. In this way show that ⟨1r⟩n,l,m=μZe2ℏ2n2=Zμcαℏn2=Za0n2\left\langle \frac{1}{r} \right\rangle_{n,l,m} = \frac{\mu Z e^2}{\hbar^2 n^2} = \frac{Z\mu c\alpha}{\hbar n^2} = \frac{Z}{a_0 n^2}

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