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Mathematics
Mathematics
Problem
Derive the identity
tan
3
θ
=
3
tan
θ
−
tan
3
θ
1
−
3
tan
2
θ
\displaystyle \tan 3\theta = \dfrac{3\tan\theta - \tan^{3}\theta}{1 - 3\tan^{2}\theta}
tan
3
θ
=
1
−
3
tan
2
θ
3
tan
θ
−
tan
3
θ
, where
θ
≠
π
2
+
n
π
\theta \neq \frac{\pi}{2} + n\pi
θ
=
2
π
+
nπ
.
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