Mathematics

Mathematics

Problem

The sum ∑n=1∞tan⁡−1(4nn4−2n2+2)\sum_{n=1}^{\infty} \tan^{-1}\left(\frac{4n}{n^4 - 2n^2 + 2}\right) is equal to a. tan⁡−112+tan⁡−123\tan^{-1}\frac{1}{2} + \tan^{-1}\frac{2}{3} b. 4tan⁡−114\tan^{-1}1 c. π2\frac{\pi}{2} d. sec⁡−1(−2)\sec^{-1}(-\sqrt{2})

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