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Mathematics
Problem
If lines
x
=
y
=
z
x = y = z
x
=
y
=
z
and
x
=
y
2
=
z
3
x = \frac{y}{2} = \frac{z}{3}
x
=
2
y
=
3
z
and third line passing through
(
1
,
1
,
1
)
(1, 1, 1)
(
1
,
1
,
1
)
form a triangle of area
6
\sqrt{6}
6
units, then point of intersection of third line with second line will be a.
(
1
,
2
,
3
)
(1, 2, 3)
(
1
,
2
,
3
)
b.
(
2
,
4
,
6
)
(2, 4, 6)
(
2
,
4
,
6
)
c.
(
4
3
,
8
3
,
12
3
)
\left(\frac{4}{3}, \frac{8}{3}, \frac{12}{3}\right)
(
3
4
,
3
8
,
3
12
)
d. None of these
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