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Mathematics
Mathematics
Problem
The curves
r
=
2
sin
θ
r=2\sin\theta
r
=
2
sin
θ
and
r
=
2
cos
θ
r=2\cos\theta
r
=
2
cos
θ
intersect at
θ
=
π
4
\theta=\tfrac{\pi}{4}
θ
=
4
π
. Determine the exact area, in square units, of the region in the first quadrant that lies inside
r
=
2
sin
θ
r=2\sin\theta
r
=
2
sin
θ
and outside
r
=
2
cos
θ
r=2\cos\theta
r
=
2
cos
θ
.
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