For the reaction 2N2O5(g)→4NO2(g)+O2(g), which statement best predicts the sign of ΔS∘ for the reaction?
a) ΔS∘>0 because the reaction is exothermic and entropy always increases when heat is released.
b) ΔS∘<0 because the total number of moles of gas decreases from 4 to 3.},{
c) ΔS∘>0 because the total number of moles of gas increases.
d) ΔS∘<0 because decomposition produces more ordered products.