Chemistry

Problem

The standard reduction potentials

E^{\circ}

for the half reaction are as

\text{Zn} \rightarrow \text{Zn}^{2+} + 2\text{e}^- \quad E^{\circ} = 0.76

\text{Fe} \rightarrow \text{Fe}^{2+} + 2\text{e}^- \quad E^{\circ} = 0.41\,\text{V}

The EMF for the cell reaction

\text{Fe}^{2+} + \text{Zn} \rightarrow \text{Zn}^{2+} + \text{Fe}

is (a)

-0.35\,\text{V}

(b)

0.35\,\text{V}

(c)

1.17\,\text{V}

(d)

-1.17\,\text{V}