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Mathematics
Mathematics
Problem
For a continuous function
h
h
h
, suppose
∫
−
4
2
h
(
t
)
d
t
=
9
\displaystyle \int_{-4}^{2} h(t)\,dt = 9
∫
−
4
2
h
(
t
)
d
t
=
9
and
∫
−
1
2
h
(
t
)
d
t
=
−
3
\displaystyle \int_{-1}^{2} h(t)\,dt = -3
∫
−
1
2
h
(
t
)
d
t
=
−
3
. Determine
∫
−
4
−
1
h
(
t
)
d
t
\displaystyle \int_{-4}^{-1} h(t)\,dt
∫
−
4
−
1
h
(
t
)
d
t
.
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