Complex Analysis: Theory and Applications · Problem 5.4.15

Complex Integration — Howell & Matthews

Mathematics — Complex Analysis · harmonic-functions

Problem

Given an elegant argument that explains why the following functions are harmonic. (a) h(x,y)=sin⁡xcosh⁡yh(x,y) = \sin x \cosh y. (b) h(x,y)=cos⁡xsinh⁡yh(x,y) = \cos x \sinh y. (c) h(x,y)=sinh⁡xcos⁡yh(x,y) = \sinh x \cos y. (d) h(x,y)=cosh⁡xsin⁡yh(x,y) = \cosh x \sin y.

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