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Chemistry
Chemistry
Problem
The wave function (
ψ
\psi
ψ
) of
2
s
2s
2
s
-orbital is given by:
Ψ
2
s
=
1
2
32
π
[
1
a
0
]
3
/
2
[
2
−
r
a
0
]
e
−
r
/
2
a
0
\Psi_{2s} = \frac{1}{2\sqrt{32\pi}} \left[ \frac{1}{a_0} \right]^{3/2} \left[ 2 - \frac{r}{a_0} \right] e^{-r/2a_0}
Ψ
2
s
=
2
32
π
1
[
a
0
1
]
3/2
[
2
−
a
0
r
]
e
−
r
/2
a
0
At
r
=
r
0
r = r_0
r
=
r
0
, a radial node is formed. Calculate
r
0
r_0
r
0
in terms of
a
0
a_0
a
0
.
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