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Mathematics
Mathematics
Problem
Show that the middle term in the expansion of
(
1
+
x
)
2
n
(1+x)^{2n}
(
1
+
x
)
2
n
is
1
⋅
3
⋅
5
…
(
2
n
−
1
)
n
!
⋅
2
n
x
n
,
n
being a positive integer.
\frac{1 \cdot 3 \cdot 5 \dots (2n-1)}{n!} \cdot 2^n x^n, n \text{ being a positive integer.}
n
!
1
⋅
3
⋅
5
…
(
2
n
−
1
)
⋅
2
n
x
n
,
n
being a positive integer.
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