Problem

Problem

Let f(x)=e(p+1)x−exf(x) = e^{(p+1)x} - e^x for real number p>0p > 0 , then a. The value of x=spx = s_p for which f(x)f(x) is minimum, is b. Let g(t)=∫tt+1f(x)et−xdxg(t) = \int_t^{t+1} f(x)e^{t-x} dx . The value of t=tpt = t_p , for which g(t)g(t) is minimum, is c. Use the fact that 1+p2≤ep−1p≤1+p2+p21 + \frac{p}{2} \le \frac{e^p - 1}{p} \le 1 + \frac{p}{2} + p^2 ( 0<p≤10 < p \le 1 ), the value of lim⁡p→0+(sp−tp)\lim_{p \to 0^+} (s_p - t_p) is

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