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Problem
Problem
Show that
(
1
r
−
1
r
1
)
(
1
r
−
1
r
2
)
(
1
r
−
1
r
3
)
=
16
R
r
2
(
∑
a
)
2
\left(\frac{1}{r} - \frac{1}{r_1}\right)\left(\frac{1}{r} - \frac{1}{r_2}\right)\left(\frac{1}{r} - \frac{1}{r_3}\right) = \frac{16R}{r^2(\sum a)^2}
(
r
1
−
r
1
1
)
(
r
1
−
r
2
1
)
(
r
1
−
r
3
1
)
=
r
2
(
∑
a
)
2
16
R
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