Mathematics

Mathematics

Problem

Let a⃗\vec{a} , b⃗\vec{b} and c⃗\vec{c} be three unit vectors such that a⃗+b⃗+c⃗=0⃗\vec{a} + \vec{b} + \vec{c} = \vec{0} . If λ=a⃗⋅b⃗+b⃗⋅c⃗+c⃗⋅a⃗\lambda = \vec{a} \cdot \vec{b} + \vec{b} \cdot \vec{c} + \vec{c} \cdot \vec{a} and d⃗=a⃗×b⃗+b⃗×c⃗+c⃗×a⃗\vec{d} = \vec{a} \times \vec{b} + \vec{b} \times \vec{c} + \vec{c} \times \vec{a} , then the ordered pair, (λ,d⃗)(\lambda, \vec{d}) is equal to : [JEE-MAIN ONLINE-2020] (1) (−32,3a⃗×b⃗)\left(-\frac{3}{2}, 3\vec{a} \times \vec{b}\right) (3) (32,3b⃗×c⃗)\left(\frac{3}{2}, 3\vec{b} \times \vec{c}\right) (2) (−32,3c⃗×b⃗)\left(-\frac{3}{2}, 3\vec{c} \times \vec{b}\right) (4) (32,3a⃗×c⃗)\left(\frac{3}{2}, 3\vec{a} \times \vec{c}\right)

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