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Problem Let a ⃗ \vec{a} a , b ⃗ \vec{b} b and c ⃗ \vec{c} c be three unit vectors such that a ⃗ + b ⃗ + c ⃗ = 0 ⃗ \vec{a} + \vec{b} + \vec{c} = \vec{0} a + b + c = 0 . If λ = a ⃗ ⋅ b ⃗ + b ⃗ ⋅ c ⃗ + c ⃗ ⋅ a ⃗ \lambda = \vec{a} \cdot \vec{b} + \vec{b} \cdot \vec{c} + \vec{c} \cdot \vec{a} λ = a ⋅ b + b ⋅ c + c ⋅ a and d ⃗ = a ⃗ × b ⃗ + b ⃗ × c ⃗ + c ⃗ × a ⃗ \vec{d} = \vec{a} \times \vec{b} + \vec{b} \times \vec{c} + \vec{c} \times \vec{a} d = a × b + b × c + c × a , then the ordered pair, ( λ , d ⃗ ) (\lambda, \vec{d}) ( λ , d ) is equal to : [JEE-MAIN ONLINE-2020]
(1) ( − 3 2 , 3 a ⃗ × b ⃗ ) \left(-\frac{3}{2}, 3\vec{a} \times \vec{b}\right) ( − 2 3 , 3 a × b )
(3) ( 3 2 , 3 b ⃗ × c ⃗ ) \left(\frac{3}{2}, 3\vec{b} \times \vec{c}\right) ( 2 3 , 3 b × c )
(2) ( − 3 2 , 3 c ⃗ × b ⃗ ) \left(-\frac{3}{2}, 3\vec{c} \times \vec{b}\right) ( − 2 3 , 3 c × b )
(4) ( 3 2 , 3 a ⃗ × c ⃗ ) \left(\frac{3}{2}, 3\vec{a} \times \vec{c}\right) ( 2 3 , 3 a × c )
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