Blundell Thermal Physics · Problem 29.5

Bose–Einstein and Fermi–Dirac distributions

Physics — Statistical Mechanics · ortho-para-hydrogen-statistics

Problem

Hydrogen (H2_2) gas can exist in two forms. If the proton spins are in an exchange symmetric triplet (S=1S = 1) state, it is known as orthohydrogen. If the proton spins are in an exchange antisymmetric singlet (S=0S = 0) state, it is known as para-hydrogen. The symmetry of the total wave function must be antisymmetric overall, so that the rotational part of the wave function must be antisymmetric for ortho-hydrogen (so that the angular momentum quantum number JJ is 1,3,5,…1, 3, 5, \ldots) or symmetric for para-hydrogen (so that J=0,2,4,…J = 0, 2, 4, \ldots). The proton separation in H2_2 is 7.4×10−117.4 \times 10^{-11} m. Estimate the spacing in kelvin between the ground state and first excited state in para-hydrogen. Show that the ratio ff of ortho-hydrogen to para-hydrogen is given by f=3∑J=1,3,5,…(2J+1)e−J(J+1)ℏ2/2IkBT∑J=0,2,4,…(2J+1)e−J(J+1)ℏ2/2IkBT,(29.39)f = 3\frac{\sum_{J=1,3,5,\ldots}(2J+1)\mathrm{e}^{-J(J+1)\hbar^2/2Ik_{\mathrm{B}}T}}{\sum_{J=0,2,4,\ldots}(2J+1)\mathrm{e}^{-J(J+1)\hbar^2/2Ik_{\mathrm{B}}T}}, \tag{29.39} and find ff at 50 K.

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