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Problem
Problem
Let
f
:
(
2
,
3
)
→
(
0
,
1
)
f: (2, 3) \rightarrow (0, 1)
f
:
(
2
,
3
)
→
(
0
,
1
)
be defined by
f
(
x
)
=
x
−
[
x
]
f(x) = x - [x]
f
(
x
)
=
x
−
[
x
]
then
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
equals (a)
x
−
2
x - 2
x
−
2
(b)
x
+
1
x + 1
x
+
1
(c)
x
−
1
x - 1
x
−
1
(d)
x
+
2
x + 2
x
+
2
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