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Chemistry
Chemistry
Problem
Calculate the dissociation constant of
N
H
4
O
H
NH_4OH
N
H
4
O
H
at
25
∘
C
25^\circ C
2
5
∘
C
, if
Δ
H
∘
\Delta H^\circ
Δ
H
∘
and
Δ
S
∘
\Delta S^\circ
Δ
S
∘
for the given changes are as follows : -
N
H
3
+
H
+
⇌
N
H
4
+
;
Δ
H
∘
=
−
52.2
kJ mol
−
1
NH_3 + H^+ \rightleftharpoons NH_4^+; \quad \Delta H^\circ = -52.2 \text{ kJ mol}^{-1}
N
H
3
+
H
+
⇌
N
H
4
+
;
Δ
H
∘
=
−
52.2
kJ mol
−
1
-
H
2
O
⇌
H
+
+
O
H
−
;
Δ
H
∘
=
56.6
kJ mol
−
1
H_2O \rightleftharpoons H^+ + OH^-; \quad \Delta H^\circ = 56.6 \text{ kJ mol}^{-1}
H
2
O
⇌
H
+
+
O
H
−
;
Δ
H
∘
=
56.6
kJ mol
−
1
-
N
H
4
O
H
⇌
N
H
4
+
+
O
H
−
;
Δ
S
∘
=
−
76.53
JK
−
1
mol
−
1
NH_4OH \rightleftharpoons NH_4^+ + OH^-; \quad \Delta S^\circ = -76.53 \text{ JK}^{-1} \text{ mol}^{-1}
N
H
4
O
H
⇌
N
H
4
+
+
O
H
−
;
Δ
S
∘
=
−
76.53
JK
−
1
mol
−
1
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