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Problem
Problem
The sides of a triangle are in AP. If the angles
A
A
A
and
C
C
C
are the greatest and smallest angle respectively, then
4
(
1
−
cos
A
)
(
1
−
cos
C
)
4(1 - \cos A)(1 - \cos C)
4
(
1
−
cos
A
)
(
1
−
cos
C
)
is equal to a.
cos
A
−
cos
C
\cos A - \cos C
cos
A
−
cos
C
b.
cos
A
cos
C
\cos A \cos C
cos
A
cos
C
c.
cos
A
+
cos
C
\cos A + \cos C
cos
A
+
cos
C
d.
cos
C
−
cos
A
\cos C - \cos A
cos
C
−
cos
A
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