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Mathematics
Mathematics
Problem
Let
x
=
2
t
1
+
t
2
x=\dfrac{2t}{1+t^{2}}
x
=
1
+
t
2
2
t
and
y
=
1
−
t
2
1
+
t
2
y=\dfrac{1-t^{2}}{1+t^{2}}
y
=
1
+
t
2
1
−
t
2
for real numbers
t
t
t
. For which value(s) of
t
t
t
does the curve have a vertical tangent line? a)
t
=
0
t=0
t
=
0
b)
t
=
±
1
2
t=\pm \dfrac{1}{\sqrt{2}}
t
=
±
2
1
c)
t
=
±
1
t=\pm 1
t
=
±
1
d) The curve has no vertical tangent line.
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