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Physics
Physics
Problem
A particle is moving in a circular path of radius
a
a
a
under the action of an attractive potential
U
=
−
k
2
r
2
U = -\frac{k}{2r^2}
U
=
−
2
r
2
k
. Its total energy is: a.
−
k
4
a
2
-\frac{k}{4a^2}
−
4
a
2
k
b.
k
2
a
2
\frac{k}{2a^2}
2
a
2
k
c. zero d.
−
3
2
k
a
2
-\frac{3}{2}\frac{k}{a^2}
−
2
3
a
2
k
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