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Chemistry
Chemistry
Problem
Calculate the electronegativity of fluorine from the following data:
E
H
−
H
=
104.2
kcal mol
−
1
E_{H-H} = 104.2 \text{ kcal mol}^{-1}
E
H
−
H
=
104.2
kcal mol
−
1
E
F
−
F
=
36.6
kcal mol
−
1
E_{F-F} = 36.6 \text{ kcal mol}^{-1}
E
F
−
F
=
36.6
kcal mol
−
1
E
H
−
F
=
134.6
kcal mol
−
1
E_{H-F} = 134.6 \text{ kcal mol}^{-1}
E
H
−
F
=
134.6
kcal mol
−
1
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