Chemistry

Chemistry

Problem

Calculate the electronegativity of fluorine from the following data: EH−H=104.2 kcal mol−1E_{H-H} = 104.2 \text{ kcal mol}^{-1} EF−F=36.6 kcal mol−1E_{F-F} = 36.6 \text{ kcal mol}^{-1} EH−F=134.6 kcal mol−1E_{H-F} = 134.6 \text{ kcal mol}^{-1}

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