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Physics
Physics
Problem
A glass pane is
0.008
m
0.008\,\text{m}
0.008
m
thick and has an area of
0.40
m
2
0.40\,\text{m}^2
0.40
m
2
. One surface is at
30
∘
C
30^\circ\text{C}
3
0
∘
C
and the other at
20
∘
C
20^\circ\text{C}
2
0
∘
C
. The thermal conductivity of glass is
k
=
0.80
W
m
−
1
K
−
1
k = 0.80\,\text{W}\,\text{m}^{-1}\,\text{K}^{-1}
k
=
0.80
W
m
−
1
K
−
1
. Calculate the steady-state rate at which energy is conducted through the pane.
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