Physics

Problem

A spherical body of radius

R

consists of a fluid of constant density and is in equilibrium under its own gravity. If

P(r)

is the pressure at

r(r < R)

, then the correct option(s) is (are) a.

P(r=0)=0

\frac{P(r=3R/4)}{P(r=2R/3)} = \frac{63}{80}

\frac{P(r=3R/5)}{P(r=2R/5)} = \frac{16}{21}

\frac{P(r=R/2)}{P(r=R/3)} = \frac{20}{27}