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Chemistry
Chemistry
Problem
A limestone block has a mass of 0.250 kg and is assumed to be pure calcium carbonate, CaCO
3
_3
3
. Determine the amount of CaCO
3
_3
3
, in moles, present in the block. (Molar mass of CaCO
3
_3
3
= 100.09 g mol
−
1
^{-1}
−
1
.) a)
0.400
mol
0.400\ \text{mol}
0.400
mol
b)
2.50
mol
2.50\ \text{mol}
2.50
mol
c)
6.23
mol
6.23\ \text{mol}
6.23
mol
d)
0.00250
mol
0.00250\ \text{mol}
0.00250
mol
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