Chemistry

Chemistry

Problem

A limestone block has a mass of 0.250 kg and is assumed to be pure calcium carbonate, CaCO3_3. Determine the amount of CaCO3_3, in moles, present in the block. (Molar mass of CaCO3_3 = 100.09 g mol−1^{-1}.) a) 0.400 mol0.400\ \text{mol} b) 2.50 mol2.50\ \text{mol} c) 6.23 mol6.23\ \text{mol} d) 0.00250 mol0.00250\ \text{mol}

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