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Mathematics
Mathematics
Problem
If
sin
θ
−
cos
θ
=
1
4
\sin\theta-\cos\theta=\dfrac14
sin
θ
−
cos
θ
=
4
1
and
θ
\theta
θ
is in Quadrant I, then
sin
θ
+
cos
θ
\sin\theta+\cos\theta
sin
θ
+
cos
θ
equals a)
−
31
4
-\dfrac{\sqrt{31}}{4}
−
4
31
b)
31
4
\dfrac{\sqrt{31}}{4}
4
31
c)
15
4
\dfrac{\sqrt{15}}{4}
4
15
d)
31
8
\dfrac{\sqrt{31}}{8}
8
31
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