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Mathematics
Mathematics
Problem
8.
∫
2
x
−
1
(
x
−
1
)
(
x
+
2
)
(
x
−
3
)
d
x
=
A
log
∣
x
−
1
∣
8. \int \frac{2x-1}{(x-1)(x+2)(x-3)} dx = A \log|x-1|
8.
∫
(
x
−
1
)
(
x
+
2
)
(
x
−
3
)
2
x
−
1
d
x
=
A
lo
g
∣
x
−
1∣
+
B
log
∣
x
+
2
∣
B \log|x+2|
B
lo
g
∣
x
+
2∣
+
C
log
∣
x
−
3
∣
C \log|x-3|
C
lo
g
∣
x
−
3∣
+
K
K
K
, then
A
A
A
,
B
B
B
,
C
C
C
are respectively
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