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Mathematics
Problem
Determine a simplified expression in terms of
n
n
n
for
∑
k
=
0
n
(
4
k
+
5
)
\displaystyle \sum_{k=0}^{n} (4k+5)
k
=
0
∑
n
(
4
k
+
5
)
. a)
(
n
+
1
)
(
4
n
+
5
)
(n+1)(4n+5)
(
n
+
1
)
(
4
n
+
5
)
b)
(
n
+
1
)
(
2
n
+
5
)
(n+1)(2n+5)
(
n
+
1
)
(
2
n
+
5
)
c)
n
(
2
n
+
5
)
n(2n+5)
n
(
2
n
+
5
)
d)
(
n
+
1
)
(
2
n
+
3
)
(n+1)(2n+3)
(
n
+
1
)
(
2
n
+
3
)
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