Physics

Physics

Problem

The trajectory of a projectile near the surface of the earth is given as

y = 2x - 9x^2

. If it were launched at an angle

\theta_0

with speed

v_0

then (

g = 10 \text{ ms}^{-2}

): (a)

\theta_0 = \sin^{-1} \frac{1}{\sqrt{5}}

and

v_0 = \frac{5}{3} \text{ ms}^{-1}

(b)

\theta_0 = \cos^{-1} \left( \frac{2}{\sqrt{5}} \right)

and

v_0 = \frac{3}{5} \text{ ms}^{-1}

(c)

\theta_0 = \cos^{-1} \left( \frac{1}{\sqrt{5}} \right)

and

v_0 = \frac{5}{3} \text{ ms}^{-1}

(d)

\theta_0 = \sin^{-1} \left( \frac{2}{\sqrt{5}} \right)

and

v_0 = \frac{3}{5} \text{ ms}^{-1}

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