Two particles A and B, each carrying charge magnitude q, move through the same region of uniform magnetic field B. Particle A has speed vA at an angle θA to B; particle B has speed vB at an angle θB to B.
a. (i) Starting from the expression for magnetic force on a moving charge, show that the ratio of the magnitudes of the forces on A and B is FBFA=vBsinθBvAsinθA.
b. (ii) Given vA=4.0×105m s−1, vB=3.0×105m s−1, θA=60∘ and θB=45∘, calculate FA/FB.
c. (iii) If the masses of the particles are mA=2mB, compare the magnitudes of their initial accelerations in the magnetic field.