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Mathematics
Mathematics
Problem
A manufacturer’s cost (in thousands of rupees) for producing
x
x
x
units of an item is given by
C
(
x
)
=
x
3
−
6
x
2
+
9
x
+
2
,
1
≤
x
≤
4.
C(x)=x^{3}-6x^{2}+9x+2, \quad 1\le x\le 4.
C
(
x
)
=
x
3
−
6
x
2
+
9
x
+
2
,
1
≤
x
≤
4.
The number of units that minimises the cost on this interval is a)
2
2
2
b)
3
3
3
c)
1
1
1
d)
4
4
4
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