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Problem
Problem
Solve
tan
θ
+
tan
2
θ
+
tan
θ
⋅
tan
2
θ
=
1
\tan \theta + \tan 2\theta + \tan \theta \cdot \tan 2\theta = 1
tan
θ
+
tan
2
θ
+
tan
θ
⋅
tan
2
θ
=
1
.
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