Physics

Physics

Problem

Two uniformly charged co-axial, identical rings (Radius RR) are fixed as shown. A point charge q0q_0 is projected with speed V0V_0 along common axis of rings from large distance. Minimum value of V0V_0 for which the charge particle can just pass through both rings is given as V0=kqq0nmRV_0 = \sqrt{\frac{kq q_0}{nmR}}. Find nn (k=14πϵ0k = \frac{1}{4\pi\epsilon_0}). ![](https://storage.googleapis.com/diraq-contents/PROD/homework-question-parsing/marker/26605a9d814c44cfa061391e994a0a01/ec77a22da01e15158981baf4129a63b5_img.jpg) ![](https://storage.googleapis.com/diraq-contents/PROD/homework-question-parsing/marker/b3e5e7e225dc473385317496b99e07ed/f01b22e5bb303653828200595aece414_img.jpg)

Browse the problem library