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Mathematics
Mathematics
Problem
The temperature
T
T
T
(in degrees Celsius) of a cup of tea cooling in a room obeys
d
T
d
t
=
−
0.25
(
T
−
22
)
\dfrac{dT}{dt}=-0.25\bigl(T-22\bigr)
d
t
d
T
=
−
0.25
(
T
−
22
)
, with
t
t
t
in minutes and
T
(
0
)
=
92
T(0)=92
T
(
0
)
=
92
. Approximate
T
(
0.8
)
T(0.8)
T
(
0.8
)
using two equal time steps of
0.4
0.4
0.4
minute. Provide your answer to the nearest tenth of a degree.
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