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Mathematics
Mathematics
Problem
Prove that
sin
A
⋅
sin
(
60
∘
−
A
)
⋅
sin
(
60
∘
+
A
)
=
1
4
sin
3
A
\sin A \cdot \sin(60^\circ - A) \cdot \sin(60^\circ + A) = \frac{1}{4} \sin 3A
sin
A
⋅
sin
(
6
0
∘
−
A
)
⋅
sin
(
6
0
∘
+
A
)
=
4
1
sin
3
A
.
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