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18. If
A
=
[
0
−
tan
α
2
tan
α
2
0
]
\mathrm{A}=\left[\begin{array}{cc}0 & -\tan \frac{\alpha}{2} \\ \tan \frac{\alpha}{2} & 0\end{array}\right]
A
=
[
0
tan
2
α
−
tan
2
α
0
]
…
Mathematics
Problem
18. If
A
=
[
0
−
tan
α
2
tan
α
2
0
]
\mathrm{A}=\left[\begin{array}{cc}0 & -\tan \frac{\alpha}{2} \\ \tan \frac{\alpha}{2} & 0\end{array}\right]
A
=
[
0
tan
2
α
−
tan
2
α
0
]
and I is the identity matrix of order 2 , show that
I
+
A
=
(
I
−
A
)
[
cos
α
−
sin
α
sin
α
cos
α
]
I+A=(I-A)\left[\begin{array}{cc}\cos \alpha & -\sin \alpha \\ \sin \alpha & \cos \alpha\end{array}\right]
I
+
A
=
(
I
−
A
)
[
cos
α
sin
α
−
sin
α
cos
α
]
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