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Chemistry
Chemistry
Problem
The slope of the line for the graph of
log
k
\log k
lo
g
k
versus
1
T
\frac{1}{T}
T
1
for the reaction,
N
2
O
5
→
2
N
O
2
+
1
2
O
2
N_2O_5 \rightarrow 2NO_2 + \frac{1}{2}O_2
N
2
O
5
→
2
N
O
2
+
2
1
O
2
is
−
5000
-5000
−
5000
. Calculate the energy of activation of the reaction - (
kJ K
−
1
mol
−
1
\text{kJ K}^{-1} \text{mol}^{-1}
kJ K
−
1
mol
−
1
) (A) 95.7 (B) 9.57 (C) 957 (D) None
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