Mathematics

Mathematics

Problem

∫xtan⁡−1x(1+x2)3/2 dx=\int \frac{x\tan^{-1}x}{(1+x^2)^{3/2}}\,dx = (a) x+tan⁡−1x1+x2+c\frac{x + \tan^{-1}x}{\sqrt{1+x^2}} + c (b) x−tan⁡−1x1+x2+c\frac{x - \tan^{-1}x}{\sqrt{1+x^2}} + c (c) tan⁡−1x−x1+x2+c\frac{\tan^{-1}x - x}{\sqrt{1+x^2}} + c (d) None of these (a) x+tan⁡−1x1+x2+c\frac{x + \tan^{-1}x}{\sqrt{1+x^2}} + c (b) x−tan⁡−1x1+x2+c\frac{x - \tan^{-1}x}{\sqrt{1+x^2}} + c (c) tan⁡−1x−x1+x2+c\frac{\tan^{-1}x - x}{\sqrt{1+x^2}} + c (d) None of these

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