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Mathematics
Mathematics
Problem
Evaluate
∫
−
2
2
∣
x
3
−
2
x
∣
d
x
\displaystyle \int_{-2}^{2}\!\left|x^{3}-2x\right|\,dx
∫
−
2
2
x
3
−
2
x
d
x
to find the area between
y
=
x
3
−
2
x
y=x^{3}-2x
y
=
x
3
−
2
x
and the
x
x
x
-axis on the interval
[
−
2
,
2
]
[-2,\,2]
[
−
2
,
2
]
.
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