Mathematics

Mathematics

Problem

1. Solve the following pair of linear equations by the substitution method. (i) x+y=14x+y=14 (ii) s−t=3s-t=3 x−y=4x-y=4 s3+t2=6\frac{s}{3}+\frac{t}{2}=6 (iii) 3x−y=33 x-y=3 (iv) 0.2x+0.3y=1.30.2 x+0.3 y=1.3 9x−3y=99 x-3 y=9 0.4x+0.5y=2.30.4 x+0.5 y=2.3 (v) 2x+3y=0\sqrt{2} x+\sqrt{3} y=0 3x−8y=0\sqrt{3} x-\sqrt{8} y=0 (vi) 3x2−5y3=−2\frac{3 x}{2}-\frac{5 y}{3}=-2 x3+y2=136\frac{x}{3}+\frac{y}{2}=\frac{13}{6} (i) x+y=14x+y=14 x−y=4x-y=4 (ii) s−t=3s-t=3 s3+t2=6\frac{s}{3}+\frac{t}{2}=6 (iii) 3x−y=33 x-y=3 9x−3y=99 x-3 y=9 (iv) 0.2x+0.3y=1.30.2 x+0.3 y=1.3 0.4x+0.5y=2.30.4 x+0.5 y=2.3 (v) 2x+3y=0\sqrt{2} x+\sqrt{3} y=0 3x−8y=0\sqrt{3} x-\sqrt{8} y=0 (vi) 3x2−5y3=−2\frac{3 x}{2}-\frac{5 y}{3}=-2 x3+y2=136\frac{x}{3}+\frac{y}{2}=\frac{13}{6}

Browse the problem library