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Mathematics
Mathematics
Problem
If
y
=
e
x
log
x
x
2
y = \frac{e^x \log x}{x^2}
y
=
x
2
e
x
l
o
g
x
, then
d
y
d
x
=
\frac{dy}{dx} =
d
x
d
y
=
(a)
e
x
[
1
+
(
x
+
2
)
log
x
]
x
3
\frac{e^x [1 + (x + 2) \log x]}{x^3}
x
3
e
x
[
1
+
(
x
+
2
)
l
o
g
x
]
(b)
e
x
[
1
−
(
x
−
2
)
log
x
]
x
4
\frac{e^x [1 - (x - 2) \log x]}{x^4}
x
4
e
x
[
1
−
(
x
−
2
)
l
o
g
x
]
(c)
e
x
[
1
−
(
x
−
2
)
log
x
]
x
3
\frac{e^x [1 - (x - 2) \log x]}{x^3}
x
3
e
x
[
1
−
(
x
−
2
)
l
o
g
x
]
(d)
e
x
[
1
+
(
x
−
2
)
log
x
]
x
3
\frac{e^x [1 + (x - 2) \log x]}{x^3}
x
3
e
x
[
1
+
(
x
−
2
)
l
o
g
x
]
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