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Mathematics
Mathematics
Problem
Evaluate
I
=
∫
0
4
1
∣
x
−
2
∣
2
/
3
d
x
\displaystyle I=\int_{0}^{4} \frac{1}{|x-2|^{2/3}}\,dx
I
=
∫
0
4
∣
x
−
2
∣
2/3
1
d
x
. a)
6
⋅
2
2
/
3
6\cdot 2^{2/3}
6
⋅
2
2/3
b)
3
⋅
2
1
/
3
3\cdot 2^{1/3}
3
⋅
2
1/3
c)
6
⋅
2
1
/
3
6\cdot 2^{1/3}
6
⋅
2
1/3
d) Divergent because the integrand is unbounded at
x
=
2
x=2
x
=
2
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