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Mathematics
Mathematics
Problem
At
t
=
2
t=2
t
=
2
, a particle moving along a parametric path has
d
x
d
t
=
5
\dfrac{dx}{dt}=5
d
t
d
x
=
5
and
d
d
t
(
d
y
d
x
)
=
−
3
\dfrac{d}{dt}\!\left(\dfrac{dy}{dx}\right)=-3
d
t
d
(
d
x
d
y
)
=
−
3
. Indicate whether the curve is concave up or concave down with respect to the
x
x
x
–axis at this instant, and justify your answer using the sign of
d
2
y
d
x
2
\displaystyle \frac{d^{2}y}{dx^{2}}
d
x
2
d
2
y
.
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