Mathematics

Mathematics

Problem

At t=2t=2, a particle moving along a parametric path has dxdt=5\dfrac{dx}{dt}=5 and ddt ⁣(dydx)=−3\dfrac{d}{dt}\!\left(\dfrac{dy}{dx}\right)=-3. Indicate whether the curve is concave up or concave down with respect to the xx–axis at this instant, and justify your answer using the sign of d2ydx2\displaystyle \frac{d^{2}y}{dx^{2}}.

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