Differential Equations and The - Braun, Martin 7579 · Problem 2

Mathematical Control Theory: Deterministic Finite Dimensional Systems — Braun, Martin 7579

Mathematics — Calculus · sturm-liouville-not-selfadjoint

Problem

Here is the outline of a proof that LL [see Equation (3)] is not selfadjoint if b(x)≠a′(x)b(x)\neq a'(x). Observe first that if b(x)≠a′(x)b(x)\neq a'(x) and we can choose uu and vv so that v(x)u′(x)−u(x)v′(x)=b(x)−a′(x),v(x)u'(x)-u(x)v'(x)=b(x)-a'(x), then the integral in Equation (10) reduces to ∫αβ[b(x)−a′(x)]2 dx≠0.\int_\alpha^\beta [b(x)-a'(x)]^2\,dx\neq 0. The only problem is that uu and vv have to satisfy the boundary conditions (3'). To modify the proof, (a) Observe that v(x)u′(x)−u(x)v′(x)=v2(x)(uv)′.v(x)u'(x)-u(x)v'(x)=v^2(x)\left(\frac{u}{v}\right)'. (b) Choose uu, vv, and constants c1,c3,…,ck+1c_1,c_3,\ldots,c_{k+1} (with kk to be determined) so that (uv)′=c1[b(x)−a′(x)]+c3[b(x)−a′(x)]3+c5[b(x)−a′(x)]5+⋯ ,\left(\frac{u}{v}\right)'=c_1[b(x)-a'(x)]+c_3[b(x)-a'(x)]^3+c_5[b(x)-a'(x)]^5+\cdots, uu and vv satisfy the boundary conditions (3'), and the integral in Equation (10) is ≠0\neq 0.

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