lim⁡n→∞12n+22(n−1)+32(n−2)+⋯+n2⋅113+23+33+⋯+n3\lim_{n \to \infty} \frac{1^2 n + 2^2 (n-1) + 3^2 (n-2) + \dots + n^2 \cdot 1}{1^3 + 2^3 + 3^3 + \dots + n^3}…

Problem

lim⁡n→∞12n+22(n−1)+32(n−2)+⋯+n2⋅113+23+33+⋯+n3\lim_{n \to \infty} \frac{1^2 n + 2^2 (n-1) + 3^2 (n-2) + \dots + n^2 \cdot 1}{1^3 + 2^3 + 3^3 + \dots + n^3} is equal to a. 13\frac{1}{3} b. 23\frac{2}{3} c. 12\frac{1}{2} d. 16\frac{1}{6}

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