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Mathematics
Mathematics
Problem
If the tangents drawn at the points
O
(
0
,
0
)
O(0, 0)
O
(
0
,
0
)
and
P
(
1
+
5
,
2
)
P(1+\sqrt{5}, 2)
P
(
1
+
5
,
2
)
on the circle
x
2
+
y
2
−
2
x
−
4
y
=
0
x^2 + y^2 - 2x - 4y = 0
x
2
+
y
2
−
2
x
−
4
y
=
0
intersect at the point
Q
Q
Q
, then the area of the triangle
O
P
Q
OPQ
O
P
Q
is equal to (a)
3
+
5
2
\frac{3+\sqrt{5}}{2}
2
3
+
5
(b)
4
+
2
5
2
\frac{4+2\sqrt{5}}{2}
2
4
+
2
5
(c)
5
+
3
5
2
\frac{5+3\sqrt{5}}{2}
2
5
+
3
5
(d)
7
+
3
5
2
\frac{7+3\sqrt{5}}{2}
2
7
+
3
5
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