Physics

Problem

The value of acceleration due to gravity is

g_1

at a height

h = \frac{R}{2}

(

R

= radius of the earth) from the surface of the earth. It is again equal to

g_1

and a depth

d

below the surface of the earth. The ratio

\left( \frac{d}{R} \right)

equals : a.

\frac{4}{9}

\frac{5}{9}

\frac{1}{3}

\frac{7}{9}